1.

A proton of mass 'm' moving with a speed v (lt lt c, velocity of light in vaccuum) completes a circular orbit in time 'T' in a uniform magnetic field. If the speed of the proton is increased to sqrt2v, what will be time needed to complete the circular orbit?

Answer»

`sqrt2T`
T
`(T)/(SQRT2)`
`(T)/(2)`

Solution :`:.` The time period of the revolving charge is, `T= (2pi R)/(v)= (2pi)/(v) XX (mv)/(QB) or T= (2pi m)/(qB)` (Using `r= (mv)/(qB)`)
Here T is independent of v. So there is no CHANGE in the time period of proton if speed is increased to `sqrt2v`.


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