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A pulse is started at a time `t = 0` along the `+x` directions an a long, taut string. The shaot of the puise at `t = 0` is given by funcation `y` with `y = {{:((x)/(4)+1fo r-4ltxle0),(-x+1fo r0ltxlt1),("0 otherwise"):}` here `y` and `x` are in centimeters. The linear mass density of the string is `50 g//m` and it is under a tension of `5N`, The transverse velocity of the particle at `x = 13 cm` and `t = 0.015 s` will beA. `-250 cm//s`B. `-500 cm//s`C. `500 cm//s`D. `-1000 cm//s` |
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Answer» Correct Answer - A Transverse velocity `= (dely)/(delt)` at `t = 0.015 s, vt = 15 cm` as for `x = 13 cm(vt - 4) lt x lt vt` therfore `(dely)/(delt) = -(v)/(4) = -250 cm//s` |
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