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A pulse is started at a time `t=0` along the `+x`direction on a long, taut string. The shape of the pulse at `t=0` is given by function `f(x)` with here `f` and `x` are in centimeters. The linear mass density of the string is `50 g//m` and it is under a tension of `5N`. The transverse velocity of the particle at `x=13 cm` and `t=0.015 s` will beA. `-250 cm//s`B. `-500 cm//s`C. `500 cm//s`D. `-1000 cm//s` |
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Answer» Correct Answer - a Transverse velocity `=(dely)/(delt)att=0.015 s, vt=15 cm` As for `x=13 cm` `(vt-4)ltxltvt` Therefore, `(dely)/(delt)=-(v)/(4)=-250 cm//s` |
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