1.

A pump is required to lift `1000kg` of water per minute from a well `20m` deep and eject it at a rate of `20ms^-1`. a. How much work is done in lifting water? b. How much work is done in giving in KE? c. What HP(horsepower) engine is required for the purpose of lifting water?

Answer» Work done in lifting water=Gain in PE(potential energy)
Work`=1000xxgxx20=1.96xx10^5Jmin^-1`
Work done(per minute) in giving it KE
`=1/2mv^2=1/2(1000)(20)^2=2xx10^5Jmin^-1`
Power of the engine=Work done per second
`=1/60(1.96+2)xx10^5J=6.6xx10^3W`
Since `1HP=746W`, HP required `=8.85`.


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