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A pump is required to lift `1000kg` of water per minute from a well `20m` deep and eject it at a rate of `20ms^-1`. a. How much work is done in lifting water? b. How much work is done in giving in KE? c. What HP(horsepower) engine is required for the purpose of lifting water? |
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Answer» Work done in lifting water=Gain in PE(potential energy) Work`=1000xxgxx20=1.96xx10^5Jmin^-1` Work done(per minute) in giving it KE `=1/2mv^2=1/2(1000)(20)^2=2xx10^5Jmin^-1` Power of the engine=Work done per second `=1/60(1.96+2)xx10^5J=6.6xx10^3W` Since `1HP=746W`, HP required `=8.85`. |
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