InterviewSolution
Saved Bookmarks
| 1. |
A pump is used to fill a tank 6m × 3m × 2m in half an hour. If the average height to which water to be lifted from the well is 110m, find the horsepower of the engine. |
|
Answer» Volume of the tank = 6 × 3 × 2 = 36m3 ∴ mass of water to be lifted = V × d = 36 × 103 kg ∴ Work done = mg × h = 36 × 103 × 9.8 × 110 Power of the pump = \(\frac{w}{t}\) = \(\frac{36 \times 9.8\times1.1 \times 10^5}{30 \times60}\)= 0.216 × 105W =\(\frac{0.216\times 10^5}{30 \times746}\) = \(\frac{21600}{746}\) 28.9 HP. |
|