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A pure inductor of 25.0 mH is connected to a sourceof 220V . Find the inductivereactance and rms current in the circuit if the frequency of the source is 50 Hz . |
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Answer» SOLUTION :`X_L= 2pi V L = 2 xx 3.14 xx 50 xx 25 xx 10^(-3)W= 7.8 Omega` The rms current in the circuit is `I = (V)/(X_L) = (220V)/(7.85 Omega) = 28A` |
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