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A pure inductor of 25.0 mH is connected to a source of 220 V. Find the inductive reactance and rms current in the circuit if the frequency of the source is 50 Hz. |
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Answer» SOLUTION :The inductive reactance, `X_(L)=2pi vL=2xx3.14xx50xx25xx10^(-3)OMEGA` `=7.85Omega` The RMS current in the circuit is `I=(V)/(X_(L))=(220V)/(7.85Omega)=28A` |
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