InterviewSolution
Saved Bookmarks
| 1. |
A purple coloured solution is made alkaline with KOH and is treated with KI forming potassium iodate. The same solution is acidified with H_(2) SO_(4) and again it is treated with Kl. However this time instead of potassium iodate, iodine gas is released. The purple coloured solution is of |
|
Answer» `K_(2)Cr_(2)O_(7)` |
|