A Purse Contains 342 Coins Consisting Of One Rupees, 50 Paise And 25

1.	A Purse Contains 342 Coins Consisting Of One Rupees, 50 Paise And 25 Paise Coins. If Their Values Are In The Ratio Of 11 : 9 : 5 Then Find The Number Of 50 Paise Coins?
Answer» Let the value of one rupee, 50 paise and 25 paise be 11x, 9x, 5X respectively. No. of 1 rupee coins = (11x / 1) =11x No. of 50 paise coins = (9x / 0.5) = 18X No. of 25 paise coins = (5x / 0.25) = 20x 11x + 18x + 9x = 342 38x = 342 x = 9 Therefore, no. of 1 rupee coins = 11 x 9 = 99 coins No. of 50 paise coins = 18 x 9 = 162 coins No. of 25 paise coins = 20 x 9 = 180 coins. Let the value of one rupee, 50 paise and 25 paise be 11x, 9x, 5x respectively. No. of 1 rupee coins = (11x / 1) =11x No. of 50 paise coins = (9x / 0.5) = 18x No. of 25 paise coins = (5x / 0.25) = 20x 11x + 18x + 9x = 342 38x = 342 x = 9 Therefore, no. of 1 rupee coins = 11 x 9 = 99 coins No. of 50 paise coins = 18 x 9 = 162 coins No. of 25 paise coins = 20 x 9 = 180 coins.

A Purse Contains 342 Coins Consisting Of One Rupees, 50 Paise And 25 Paise Coins. If Their Values Are In The Ratio Of 11 : 9 : 5 Then Find The Number Of 50 Paise Coins?

Answer»

Let the value of one rupee, 50 paise and 25 paise be 11x, 9x, 5X respectively.

No. of 1 rupee coins = (11x / 1) =11x

No. of 50 paise coins = (9x / 0.5) = 18X

No. of 25 paise coins = (5x / 0.25) = 20x

11x + 18x + 9x = 342

38x = 342

x = 9

Therefore, no. of 1 rupee coins = 11 x 9 = 99 coins

No. of 50 paise coins = 18 x 9 = 162 coins

No. of 25 paise coins = 20 x 9 = 180 coins.

Let the value of one rupee, 50 paise and 25 paise be 11x, 9x, 5x respectively.