| 1. |
A quadrilateral is divided into three triangles as shown. We know that the sum of the angles of each triangle is 180°. Thesum of the angles at the vertices of the quadrilateral is |
|
Answer» Answer: Firstly, since you haven't provided any information on the data that you already possess, I'm going to assume that: You know the values of the other 3 angles. In this case, the test condition is easy to solve: Consider a quadrilateral ABCD, whose 4 angles are ∠A,∠B,∠C and ∠D.If ∠A+∠B+∠C=180∘,then ∠D=180∘ You know the coordinates of the 4 vertices. In this case, the test condition is satisfied if: Consider a quadrilateral ABCD, with the coordinates of its 4 POINTS as A(xa,ya,ZA),B(xb,yb,zb),C(XC,yc,zc),and D(xd,yd,zd).Use the distance formula to calculate AB, BC, CA, AD, diagonals AC and BD.Now, if any two sides add up to a diagonal, you have the angle between those 2 sides as 180∘For your information, the distance formula isD(P1,P2)=(x2−x1)2+(y2−y1)2+(z2−z1)2−−−−−−−−−−−−−−−−−−−−−−−−−−−−√,where P1=(x1,y1,z1),and P2=(x2,y2,z2) I hope this answers your question, and I SUGGEST that if it didn't answer your question, please clearly STATE exactly what data you are facilitated with. thanks you |
|