InterviewSolution
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InterviewSolution
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A quantity of an ideal gas at `17^(@)C` is compressed adiabatically to `1/8th of its initial volume. Calculate the final temp. if the gas in monoatomic. |
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Answer» Here, `T_(1)= 17^(@)C= 17+273= 290K` `V_(2)= 1/8V_(1), T_(2)=?` For monoatomic gas `gamma = 5//3` As the process is adiabatic, therefore, `T_(2)V_(2)^(gamma-1)=T_(1)V_(1)^(gamma-1)` `T_(2)= T_(1)((V_(1))/(V_(2)))^(gamma-1)` `= 290(8)^(5//3-1)=(290)xx(8)^(2//3)` `= 290xx4= 1160K` |
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