1.

A quantity of PCl_(5) was heated in a 10 dm^(3) vessel at 250^(@)C : PCl_(5(g))iffPCl_(3(g))+Cl_(2(g)) At equilibrium, the vessel contains 0.1 mole of PCl_(5) and 0.2 mole of Cl_(2). The equilibrium constant of the reactionis

Answer»

`0.04`
`0.025`
`0.02`
`0.05`

Solution :`{:(,PCl_(5),IFF,PCl_(3),+,Cl_(2)),("MOLES at EQM.","0.1 mole",,"0.2 mole",,"0.2 mole"),("Molar concs.","0.1/10",,"0.2/10",,"0.2/10"):}`
`K=(0.02xx0.02)/(0.01)=0.04`


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