InterviewSolution
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InterviewSolution
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A quarter cylinder of radius R and refractive index 1.5 is placed on a table.A point object P is kept at a distance of mR from it. Find the value of m for whicha ray from P will emerge parallel to the table as shown in the figure. |
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Answer» Correct Answer - `4//3` Applying `(mu_(2))/(v) - (mu_(1))/(u) = (mu_(2) - mu_(1))/(R)` First on plane surface `(1.5)/(Al_(1)) - (1)/(-mR) = (1.5-1)/(oo) = 0` `therefore Al_(1) = -(1.5"mR")` Then on curved surface `(1)/(oo) - (1.5)/(-(1.5 mR + R)) = (1 - 1.5)/(-R)` [`v = oo` because final image is at infinity] `implies (1.5)/((1.5 m +1) R) = (0.5)/(R)` `implies 3 = 1.5 m + 1 implies (3)/(2) m = 2 implies m = (4)/(3)` |
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