1.

A quarter horse power motor runs at a speed of 600 Ep.m. Assuming 40% efficiency the work done by the motor in one rotation will be:

Answer»

7.46 J
7400 J
7.46 ergs
74.6 J

Solution :Here, speed of motor =`(600)/(60)=10 r.p.s`
POWER of motor=`1/4hp=(746)/(4)W`
EFFECTIVE power=`(40)/(100)xx(746)/(4)=74.6 W`
`Work W=("Effecttive powre")/("No. of rotations/sec")`
=`(746)/(10)=7.46 J`.


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