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A racing car has a uniform acceleration of 4 m/ s2 . what distance will it cover in 10sec after start ? pls answer fast! |
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Answer» Uniform acceleration a = 4 m/s²Initial velocity U= 0 m/sTime t = 10 sec.Velocity v after 10 sec= u + a t = 0 m/s + 4 m/s² × 10 s =40 m/s.We shall calculate the distance covered by all possible methodsUsing Average Velocity:Initial velocity u= 0 m/sFinal velocity v= 40 m/sAverage velocity= ½( u +v) = ½ ( 0+40)= 20 m/sTime= 10 sDistance covered in 10 s= av. VEL. × time= 20m/s × 10S = 200 mUsing the relation s = u t+ ½ a t²u = 0 m/s, a = 4 m/s², t= 10 sec.s = 0×10 + ½ 4× 10² = 200 mUsing the relation v² - u² = 2 a s,u = 0 m/s, v= 40 m/s, a= 4 m/s²s = 1/2 a ( v² - u²)= 1/2×4 ( 40² - 0²) = 1/8(1600–0)= 1600/8= 200 m.So all relations give the same results as it should.Explanation:MARK me as brainlieast |
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