1.

A radiation of energy 'E' falls normally on a perfectly reflecting surface. The momentum transferred to the surface is (c = Velocity of light) :

Answer»

<P>`(E )/(c )`
`(2E)/(c )`
`(2E)/(c^(2))`
`(E )/(c^(2))`

SOLUTION :MOMENTUM of radiation `p = (E )/(c )`
Momentum transferred to the surface `= p_(f)-p_(i)`

`=(E )/(c )-(-(E )/(c ))`
`= (2E)/(c )`


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