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A radiation of energy E falls normally on a perfectly reflecting surface. The momentum transferred to the surface is |
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Answer» Solution :Initial momentum of RADIATION, `P_(1)=(E )/(C )` Final momentum of radiation, `P_(2)=-(E )/(C )` `:.` Momentum transferred to the surface `=P_(1)-P_(2)=(2E)/(C )` Thus Correct choice is (d). |
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