A radio - active sample of half- life 10 days contains 1000 x nuclei . Number of original nuclie present after 5 days is

A radio - active sample of half- life 10 days contains 1000 x nuclei .

1.	A radio - active sample of half- life 10 days contains 1000 x nuclei . Number of original nuclie present after 5 days is
Answer» 707x 750x 500x 250x Solution :`N=(N_(0))/(2^(n))` Here `n=(1)/(2)` and `N_(0)=1000x` `THEREFORE N=(1000x)/(2^((1)/(2)))=(1000x)/(SQRT(2))=0.707xx1000x` `N=707x`

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A radio - active sample of half- life 10 days contains 1000 x nuclei . Number of original nuclie present after 5 days is

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