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A radio can tune over the frequency range of a portion of MW broadcast band: (800 kHz to 1200 kHz). If its LC circuit has an effective inductance of 200 muH, what must be the range of its variable capacitor? |
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Answer» Solution :`v=(1)/(2pi) sqrt((1)/(LC)), i.e., C=(1)/(4pi^(2)v^(2)L)` For `L=200muH, v=1200kHz, C=87.9pF`. For `L=200muH, v=800kHz, C=197.8pF`. The variable CAPACITOR should have a RANGE of about 88 pF to 198 pF. |
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