1.

A radioactive element decays by following three different parallel paths : A overset(lambda_(1))(to) B, lambda_(1) = 5 xx 10^(-2) sec^(-1) 2A overset(lambda_(2))(to) C,lambda_(2) = 3xx10^(-2) sec^(-1) 3A overset(lambda_(3))(to) D, lambda_(3) = 5xx10^(-3) sec^(-1) Calculate average life- time of element (in sec.) [lambda_(1), lambda_(2), lambda_(3) "are decay constans forrespective reactions"]

Answer»


ANSWER :8


Discussion

No Comment Found