1.

A radioactive element with half-life 6.5 hr has 48 xx 10^(19) atoms. Number of atoms left after 26 hr

Answer»

`24 xx 10^(19)`
`12 xx 10^(19)`
`3 xx 10^(19)`
`6 xx 10^(19)`

SOLUTION :`N_(t) = N_(0) ((1)/(2))^(n) = 48xx10^(19) ((1)/(2))^(26//65)`
`= 48 xx 10^(19) ((1)/(2))^(4) = 3xx 10^(19)`


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