1.

A radioactive isotope decays at such a rate that after 192 minutes only 1/16 of the original amount remains. The half-life of the radioactive isotope is

Answer»

32 MIN
48 min
12 min
24 min

Solution :`K=(2.303)/(192)log16`
`t_(1//2)-(0.693)/(K)=(0.693)/((2.303)/(192)xx4log2)=48min`


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