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A radioactive isotope decays at such a rate that after 192 minutes only 1/16 of the original amount remains. The half-life of the radioactive isotope is |
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Answer» Solution :`K=(2.303)/(192)log16` `t_(1//2)-(0.693)/(K)=(0.693)/((2.303)/(192)xx4log2)=48min` |
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