1.

A radioactive isotope decays at such a rate that after 96 minutes only (1)/(8)th of the original amount remains. The half-life of this nuclide in minutes is

Answer»

12
24
32
48

Solution :`lamda = (2.303)/(t) "LOG" ([N_(0)])/([N]) = (2.303)/(96) "log" (1)/(1//8)`
`:. T_(1//2) = (0.693)/(lamda) = (0.693)/(0.0216) = 32.0` MIN


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