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A radioactive isotope has a half-life of 10 year.How long will it take for the activity to reduce to 3-125% ? |
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Answer» Solution :We have ` ""= 3.125% =( 3.125)/( 100) = (1)/(32) = (1)/(2^(5))` Half life =10 years ` therefore `Required time `= 5xx 10 `years `""= `50 years |
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