1.

A radioactive isotope has a half-life of 27 days. Starting with 4g of the isotope, what will be mass remaining after 75 days

Answer»

100g
50g
0.58 g
1.58 g

Solution :`k = (0.693)/(t_(1//2))`
`t = (2.303)/(k) "LOG" (N_(0))/(N)`
`t_(1//2) = 27` days
`k = (0.693)/(27) = 0.0257 "DAY"^(-1)`
`t = (2.303)/(0.0257) "log" (N_(0))/(N)`
`N_(0) = 4g, N =? , t = 75` days
`75 = (2.303)/(0.0257) "log"(4)/(N)`
`N = 0.58g`


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