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A radioactive isotope has a life of T years. How long will it take the activity to reduce to (a) `1%` of its original activity?A. `3.2T yr`B. `4.6T yr`C. `6.6T yr`D. `9.2T yr` |
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Answer» Correct Answer - C form `A=A_(0)=N/(N_(0)) =(1/2)^(n) =1/100` `:. n(log1-log2)=log1-log100` `n(0-0.3010)=0-2` `n=2/0.3010=6.6` `t=nT=6.6Tyrs` |
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