1.

A radioactive isotope having a half life of 2.3 days was received after 9.2 days. It was found that there were 300mg of the isotope in the container. The initial amount of the isotope was

Answer»

1200mg
3600mg
4800 MG
2400mg

Solution :`t_(1//2) = (0.693)/(K) RARR k = (0.693)/(2.3) = 0.3013`
`t= (2.303)/(k) "log" (N_(0))/(N_(t)) rArr "log" (N_(0))/(N_(t)) = (kt)/(2.303)`
`rArr log N_(0) - log N_(t) = (kt)/(2.303)`
`log N_(0) = (0.3013 xx 9.2)/(2.303) + 2.4771 , N_(0) = 4800 mg`.


Discussion

No Comment Found

Related InterviewSolutions