1.

A radioactive isotope having a half life of 2.3 days was received after 9.2 days. It was found that there were 300 mg of the isotope in the container. The initial amount of the isotope was

Answer»

3600 MG
1200 mg
2400 mg
4800 mg.

Solution :9.2 days = 4 half-lives
Amount LEFT after N half-lives = `1/(2^n) XX a`
`300 = 1/(2^4) a`
or `a = 300 xx 16 = 4800` mg.


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