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A radioactive isotope X has a half life of 3 second Initially a given sample of this isotope contains 8000 atoms. Calculate (a) its decay constant , (b) the time t_1 when 1000 atoms of the isotope X remain in the sample , and (c) the number of decay per second in the sample at t =t_1. |
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Answer» Solution :(a)`lambda=0.693/T_(1//2) = 0.693/3=0.231 s^(-1)` (b)`N=N_0e^(-lambdat)` `t_1=1/lambda log_e N_0/N = 1/0.231 log_e 8000/1000`=9 SEC (c)`|(DN)/(DT)|_(t=t_1)=lambdaN=0.231xx1000=231 s^(-1)` |
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