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A radioactive nucleus ‘A’ undergoes a series of decays according to the following scheme : Aoverset(alpha)(to)A_(1)overset(beta)(to)A_(2)overset(alpha)(to)A_(3)overset(gamma)(to)A_(4) The mass number and atomic number of A are 180 and 72 respectively. What are these numbers for A_(4)? |
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Answer» Solution :As per decay series, mass number and atomic numbers of various nuclei are : `" "_(72)^(180)A OVERSET(ALPHA)(to)" "_(70)^(176)A_(1)overset(beta^(-))(to)" "_(71)^(176)A_(2)overset(alpha)(to)" "_(69)^(172)A_(3)overset(gamma)(to)" "_(69)^(172)A_(4)^(*)` Therefore, mass number of `A_(4)` is 172 and its atomic number is 69. |
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