A radioactive nucleus is being produced at a constant rate alpha per second. Its decay constant is lambda. If N_(0) are the number of nuclei at time t =0, then maximum number of nuclei possible are :

A radioactive nucleus is being produced at a constant rate alpha per s

1.	A radioactive nucleus is being produced at a constant rate alpha per second. Its decay constant is lambda. If N_(0) are the number of nuclei at time t =0, then maximum number of nuclei possible are :
Answer» `alpha/LAMBDA` `N_(0)+(alpha)/(lambda)` `N_(0)` `lambda/alpha+N_(0)` Solution :`-(d N)/(DT)=alpha` i.e. `lambda N_("max")=alpha` `N_(max)=alpha/lambda`

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A radioactive nucleus is being produced at a constant rate alpha per second. Its decay constant is lambda. If N_(0) are the number of nuclei at time t =0, then maximum number of nuclei possible are :

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