1.

A radioactive nuclide is produced at a constant rate alpha-"per second"/ It's decay constant is lambda sec^(-1). If N_(0) b the number of nuclei at time t=0, then maximum number of nuclei at any instant possible are:

Answer»

`(ALPHA)/(LAMBDA)`
`N_(0)-(alpha)/(lambda)`
`(lambda)/(alpha)`
`alpha+lambdaN_(0)`

ANSWER :A


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