1.

A radioactive nuclide X decays at the rate of 1.00 xx 10^(5) disintegration S^(-1) g^(-1). Radium decays at the rate of 3.70 xx 10^(10) disintegration s^(-1) g^(-1). The activity of X in millicurie g^(-1) (mci g^(-1)) is

Answer»

0.027
`0.270 xx 10^(-5)`
0.0027
0.00027

Solution :`(dx_(1))/(dt) = LAMDA N_(1), 1 xx 10^(5) = lamda N_(1)`
`(dx_(2))/(dt) = lamda N_(2), 3.7 xx 10^(10) = lamda N_(2)`
`(N_(1))/(N_(2)) = (1 xx 10^(5))/(3.7 xx 10^(10)) = (1 xx 10^(-5))/(3.7) = 0.27 xx 10^(-5)`


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