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A radioactive sample has an activity of4 xx10^(7) Ci , Expross its activity in .becqueral. and .rutherford.. |
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Answer» Solution : Since 1 CI=`3.7 xx10^(10)` decays per second, activity `= 4 xx10^(7) Ci= 4 xx 10^(7) xx3.7 xx 10^(10) Bq` `= 1.48 xx 10^(18) Bq` Since , `1xx10^(6)`DECAY per second = 1 RD Activity = `1.48 xx10^(18) Bq= (1.48 xx10^(18))/(1xx10^(6))Rd = 1.48 xx10^(12)Rd`. |
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