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A radioactive sample `S_1` having an activity of `5muCi` has twice the number of nuclei as another sample `S_2` which has an activity of `10muCi`. The half-lives of `S_1` and `S_2` can beA. `20` years and `5` years, respectivelyB. `20` years and `10` years, respectivelyC. `10` years eachD. `5` year each |
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Answer» Correct Answer - A Activity `=lambdaN` & `T_(1//2)=(ln2)/lambda` So `5=(ln2)/T_(1) (2N_(0))` & `10 =(ln2)/T_(2) (N_(0)) implies T_(1)=4T_(2)` |
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