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A radioactive substance decays at 1/32 of its initial activity in 25 days. Its half life is : |
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Answer» Solution :`N/N_(0)=(1/2)t/T ["t=25 days"]` `1/(32)=(1/2) (25)/T` `(1/2)^(5)=(1/2)^((25)/T)` `5=(25)/T, "T=5days"` |
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