1.

A radioactive substance decays to 1/16 th of the initial mass in 40 days. The half life of the substance is….. Day.

Answer»

20
10
5
2.5

Solution :`N/N_0=1/16=1/2^4`
`THEREFORE 1/2^n=1/2^4 therefore n=4`
Now `n=t/t_(1//2) IMPLIES t_(1//2)=t/n=40/4=10 DAYS`


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