1.

A radioactive substance emit 100 beta particfles in the first 2 s and 50 beta particles in the next 2s. The mean life of the sample is

Answer»

4 s
2 s
`(2)/(0.693)s`
`2xx0.693 s`

Solution :Given in 1ST two seconds `100beta` PARTICLES and in next two seconds `50beta` particles are EMITTED.
`:.T_(1//2)=2s`
Hence, mean life, `T=(t_(1//2))/(0.693)=(2)/(0.693)`


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