1.

A radioactive substance emits 100 beta particles in the first 2s and 50 beta particles in the next 2s. The mean life of the samnle ise

Answer»

4s
2s
`(2)/(0.693)s`
`2 XX 0.693s`

Solution :GIVEN, LN 1st two seconds `100 beta` PARTICLES and in next two seconds `50 beta` particles are EMITTED.
`T_(1//2)=2s`
Hence, `T_(m)=(T_(1//2))/(0.693)=(2)/(0.693)`


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