1.

A radioactive substance has t_(1//2) 60 minutes. After 3 hrs, what percentage of radioactive substance will remain ?

Answer»

0.5
1.75
0.25
0.125

Solution :No. of HALF lives in 3 HRS =3
`:.C_(N)=(1)/(2^(n))=(1)/(2^(3))=(1)/(8)`
`:.` AMOUNT LEFT =12.5%


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