1.

A radioactive substance is reduced to 1/8 of its original concentration in 24 s. The rate constant of the reaction is :

Answer»

`(0.69)/(16) s^(-1)`
`(1)/(8)s^(-1)`
`(1)/(24)s^(-1)`
`("In"2)/(8)s^(-1)`

Solution :(D ) `([A]_(0))/(2^(N)) = ([A]_(0))/(8) " ""or"" " 2^(n) =8 , n =3 `
`t_(1//2) = (24)/(3) = 8s`
`K = (In2)/(8) s^(-1)` .


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