1.

A radioelement has atomic number 90 and mass number 232. What is the atomic number and mass number of the end product obtained by loss of 6 - alpha and 4 - betaparticles?

Answer»

82208
88206
82206
84, 204

Solution :The nuclear reaction is
`""_(90)X^(232) to ""_(Z)Y^(A) + 6 ""_(2)alpha^(4) + 4 ""_(1)beta^(0)`
Considering MASS number,
`232 = A + 24 implies A = 208`
Considering atomic number,
`90 = Z + 12 - 4 implies Z = 82`
Now atomic number and mass number of the end PRODUCT is 82 and 208 respectively.


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