1.

A radioisotope with At. wt. 99 has a half-life of 6 hours. A solution with 10^(-12) gm of this isotope is provided to perum, Then Activity at the end of one hour is

Answer»

`3.13 xx 10^(8)//hr`
`6.26 xx 10^(8)//hr`
`9.39 xx 10^(8)//hr`
`10.2 xx 10^(7)//hr`

Solution :Now `N/N_(0) =(1/2)^(1//T)=(1/2)^(1//6)`
`N=N_(0) (1//2)^(1//6) =5.417 xx 10^(9)`
Activity after one hour is
`(dN //DT)t=1hr=lambda N=6.26 xx 10^(8)hr`


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