1.

A random, variable `X`has the following probability distribution:`X : 0 1 2 3 4 5 6 7``P(X):0 k 2k 2k 3k k^2 2k^2 7k^2+k`Find each of the following:`k`ii. `P(X

Answer» Correct Answer - A
Since the sum of the probabilities in a probability distribution is always unity.
`therefore P(X=0)+P(X=1)+.....+P(X=7)=1`
`rArr 0+k+2k+2k+3k+k^2+2k^2+7k^2+k=1`
`rArr 10k^2+9k-1=0`
`rArr (10k-1)(k+1)=0`
`rArr 10k-1=0 " "[because kge0thereforek+1 ne 0]`
`rArr k=(1)/(10)`
Now,
`P(Xge 6)=P(X=6)+P(X=7)=2k^2+7k^2+k=9k^2+k=(19)/(100)" "(k=1//10]`


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