From a box containing 20 tickets marked with numbers 1 to 20, four tickets are drawn one by one. After each draw, the ticket is replaced. The probability that the largest value of tickets drawn is 15 is.A. `((3)/(4))^4`B. `(27)/(320)`C. `(27)/(1280)`D. none of these

From a box containing 20 tickets marked with numbers 1 to 20, four tic

1.	From a box containing 20 tickets marked with numbers 1 to 20, four tickets are drawn one by one. After each draw, the ticket is replaced. The probability that the largest value of tickets drawn is 15 is.A. `((3)/(4))^4`B. `(27)/(320)`C. `(27)/(1280)`D. none of these
Answer» Correct Answer - B We,have Probability of drawing a ticket bearing number `15 is (1)/(20)`. Probability of drawing a ticket bearing a number less than or equal to `15 is (15)/(20)=(3)/(4)`. `therefore` Required probability `=` Probability of drawing one ticket bearning number 15 and three tickets bearing numbers less than or equal to `15 =.^4C_(1)xx(1)/(20)xx((3)/(4))^3=(27)/(320)`

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