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A rangeof galvanometer is V when 50 Omega resistance is connected is connected in series its rangegets doubled when 500 Omegaresistance is connectedin series galvanometerresistance is

Answer»

`100 omega`
`200 omega`
`300 omega`
`400 omega`

Solution :A galvanometeris converted into a VOLTMETER whenahigh resistance is connected to it in series
If I is maximum current flowingthroughgalvanometer then
`V= (R+G)I=(50+G)I`
where V is the rangeof galvanometerwhen R= 50 `omega`is connectedin serieswith itand g isgalvanometer resistance
when 500 `omega`resistnce is conncected in seriesthe rangebecomesdouble
`2V=(500 +G)I`
or `500 +G =100 +2Grarr G= 400 omega`


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