(a) Rate constant of a first order reaction is 0.0693 mi n^(-1). Calcu – InterviewSolution

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1.	(a) Rate constant of a first order reaction is 0.0693 mi n^(-1). Calculate the percentage of the reactant remaining at the end of 60 minutes.
Answer» Solution :`K=(2.303)/(t)"LOG"(R_(0))/(R)` `0.0693=(2.303)/(16)"log"(100)/(R)` `R=1.56%`

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