1.

A ray of light ab passing through air enters a liquid of refractive index mu_(1) at the boundary XY. In the liquid, the ray is shown as bc. The angle between ab and bc ( angle of deviation) is delta. The ray then passes through a rectangular salb ABCD of refractive index mu_(2)(mu_(2)gtmu_(1)) and emerges from the slab as the ray de. The angle between XY and AB is theta. The angle between ab and de is

Answer»

`DELTA`
`delta+theta`
`delta+sin^(-1)((mu_(1))/(mu_(2)))`
`delta+theta-sin^(-1)((mu_(1))/(mu_(2)))`

ANSWER :A


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