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A ray of light covers distance .d. in time t, in air and distance 10 d in time t_2, in medium, then critical angle for medium is ..... |
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Answer» `sin^(-1)((t_1)/(t_2))` sinC=`1/n=v/c` `therefore` sinC=`(d_m//t_2)/(d_a//t_1)` [`because d_m` and `d_a` are distances COVERED in air and medium] `thereforesinC=(d_mt_1)/(d_at_2)` `=(10d xx t_1)/(d xx t_2)` `(10t_1)/(t_2)` `therefore C=sin^(-1)((10t_1)/(t_2))` |
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