1.

A ray of light enters a spherical drop of water of refractive index mu as shown in figure. Q. Considert eh figure of question 60, the angle phi for which minimum deviation is producedwill be given by

Answer»

`cos^(2)PHI=(mu^(2)+1)/(3)`
`cos^(2)phi=(mu^(2)-1)/(3)`
`sin^(2)phi=(mu^(2)+1)/(3)`
`sin^(2)phi=(mu^(2)-1)/(3)`

Solution : `(ddelta)/(dphi)=-(4dalpha)/(dphi)+2`
`(ddelta)/(dphi)=0rArr (dalpha)/(dphi)=(1)/(2)`
`a=sin^(-1)((1)/(mu)sinphi)`
`cos^(2)phi=(mu^(2)-1)/(3)`


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